当x=2时,y=2008,代数式x2+2xy+y2/x2+y2乘以x-y/x2+xy的值=x2为x的平方
兰永杰回答:
x2+2xy+y2/x2-y2乘以x-y/x2+xy
=(x+y)^2/(x+y)(x-y)*(x-y)/(x(x+y))
=1/x
=1/2
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当x=2时,y=2008,代数式x2+2xy+y2/x2+y2乘以x-y/x2+xy的值=x2为x的平方
兰永杰回答:
x2+2xy+y2/x2-y2乘以x-y/x2+xy
=(x+y)^2/(x+y)(x-y)*(x-y)/(x(x+y))
=1/x
=1/2